256r^2-196=0

Solution for 256r^2-196=0 equation:

256r^2-196=0

a = 256; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·256·(-196)
Δ = 200704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{200704}=448$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-448}{2*256}=\frac{-448}{512}
=-7/8
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+448}{2*256}=\frac{448}{512}
=7/8
$